4y^2-4y+5=0

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Solution for 4y^2-4y+5=0 equation:


Simplifying
4y2 + -4y + 5 = 0

Reorder the terms:
5 + -4y + 4y2 = 0

Solving
5 + -4y + 4y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
1.25 + -1y + y2 = 0

Move the constant term to the right:

Add '-1.25' to each side of the equation.
1.25 + -1y + -1.25 + y2 = 0 + -1.25

Reorder the terms:
1.25 + -1.25 + -1y + y2 = 0 + -1.25

Combine like terms: 1.25 + -1.25 = 0.00
0.00 + -1y + y2 = 0 + -1.25
-1y + y2 = 0 + -1.25

Combine like terms: 0 + -1.25 = -1.25
-1y + y2 = -1.25

The y term is -1y.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1y + 0.25 + y2 = -1.25 + 0.25

Reorder the terms:
0.25 + -1y + y2 = -1.25 + 0.25

Combine like terms: -1.25 + 0.25 = -1
0.25 + -1y + y2 = -1

Factor a perfect square on the left side:
(y + -0.5)(y + -0.5) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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